Difference between revisions of "Burgers' equation"

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$$\frac{\partial u}{\partial t} + u(\nabla \cdot u) = \ni \nabla^2 u$$
+
$$\frac{\partial u}{\partial t} + u(\nabla \cdot u) = \nu \nabla^2 u$$

Revision as of 14:34, 27 December 2023

Burgers equation


$$\frac{\partial u}{\partial t} + u(\nabla \cdot u) = \nu \nabla^2 u$$