Electromagnetic scattering: Difference between revisions
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Solution to electromagnetic scattering on anisotropic cylinder |
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In this example we will showcase the ability of the medusa library to solve coupled domain problems. We will solve the problem of electromagnetic scattering on an anisotropic cylinder. | |||
== Anisotropic cylinder == | |||
Let us first quickly derive the problem we are about to solve. Beginning with the electromagnetic wave equation in anisotropic media | |||
<math> | |||
\label{eq:frekaniwave} | |||
\nabla \times \left( \underline{\varepsilon}^{-1} \nabla \times \boldsymbol{H} \right) = \omega^2 \mu_0 \varepsilon_0 \underline{\mu} \boldsymbol{H}, | |||
</math> | |||
where <math>\underline{\varepsilon}</math> is the relative dielectric tensor, and <math>\underline{\mu}</math> is the magnetic permeability tensor of the anisotropic material. | |||
Revision as of 16:57, 17 April 2019
In this example we will showcase the ability of the medusa library to solve coupled domain problems. We will solve the problem of electromagnetic scattering on an anisotropic cylinder.
Anisotropic cylinder
Let us first quickly derive the problem we are about to solve. Beginning with the electromagnetic wave equation in anisotropic media
<math> \label{eq:frekaniwave} \nabla \times \left( \underline{\varepsilon}^{-1} \nabla \times \boldsymbol{H} \right) = \omega^2 \mu_0 \varepsilon_0 \underline{\mu} \boldsymbol{H}, </math>
where <math>\underline{\varepsilon}</math> is the relative dielectric tensor, and <math>\underline{\mu}</math> is the magnetic permeability tensor of the anisotropic material.