Difference between revisions of "Integrators for time stepping"
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\end{align*} | \end{align*} | ||
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| + | where $y$ is the unknown (possibly vector) function, $t_0$ is the start time, $f$ is the derivative (the functions we wish to integrate) and $y_0$ is the initial value of $y$. | ||
| + | Numerically, we usually choose a time step $\Delta t$ and integrate the function up to a certain time $t_{\max}$. Times os subsequent time steps are denoted with $t_i$ and function values with $y_i$. | ||
| + | |||
| + | The simplest method is explicit Euler's method, stated as | ||
| + | $y_{n+1} = y_{n} + \Delta t f(t, y_n)$ | ||
Revision as of 11:51, 10 November 2017
Integrators for time stepping
We are solving an initial value problem, given as
$ \begin{align*} \dot{y}(t) &= f(t, y) \\ y(t_0) &= y_0 \end{align*} $
where $y$ is the unknown (possibly vector) function, $t_0$ is the start time, $f$ is the derivative (the functions we wish to integrate) and $y_0$ is the initial value of $y$. Numerically, we usually choose a time step $\Delta t$ and integrate the function up to a certain time $t_{\max}$. Times os subsequent time steps are denoted with $t_i$ and function values with $y_i$.
The simplest method is explicit Euler's method, stated as $y_{n+1} = y_{n} + \Delta t f(t, y_n)$
