Hertzian contact: Difference between revisions
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Created page with "Click on Solid Mechanics to go back. = Contact of two cylinders with axes parallel = If two circular cylinders with radii $R_1$ and $R_2$ are pressed together by a force..." |
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\end{equation} | \end{equation} | ||
\begin{equation} | \begin{equation} | ||
\frac{1}{E^*} = \frac{1-\nu_1^2}{E_1} + \frac{1-\nu_2^2}{E_2}. | \frac{1}{E^*} = \frac{1-{\nu_1}^2}{E_1} + \frac{1-{\nu_2}^2}{E_2}. | ||
\end{equation} | \end{equation} | ||
= FreeFem++ numerical solution = | = FreeFem++ numerical solution = | ||
Revision as of 08:43, 16 November 2016
Click on Solid Mechanics to go back.
Contact of two cylinders with axes parallel
If two circular cylinders with radii $R_1$ and $R_2$ are pressed together by a force per unit length of magnitude $F$ with their axes parallel, then the contact patch will be of half-width $b$ such that \begin{equation} b = \sqrt{\frac{2FR}{\pi E^*}} \end{equation} where $R$ and $E^*$ are the reduced radius of contact and the contact modulus defined by \begin{equation} \frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}, \end{equation} \begin{equation} \frac{1}{E^*} = \frac{1-{\nu_1}^2}{E_1} + \frac{1-{\nu_2}^2}{E_2}. \end{equation}